That is a very simple mathematics question. # i3 ]+ V/ \4 n6 o) m2 |tvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child 0 f: l+ G$ s6 x& k3 S* z) ^5 I1 }6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb7 o9 {+ K+ j1 F7 q
x + y + z = 100 Formula 2+ c K' L( U T8 ^
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3; i& r% [( H8 {3 v9 Q3 X/ [' c
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 ( H1 G$ ?: j x9 e" `6 bFormula 4 can change into 11x + 5y = 100 Formula 5 , g5 X8 F! @* q/ _, T+ XIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. 5 T/ y4 ?$ m( iwww3.tvboxnow.comAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb& I7 ~: V, V4 s) Q; t* V
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,children ; L' [# T( V b! f$ S! c }& J0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM
) q1 ~ b/ a' @! K% gwww3.tvboxnow.com11X must be 0 or multiple of 5 ( V G7 X# M% o* n8 |- fthat meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
