That is a very simple mathematics question.
( ~4 B3 ^0 n5 G; [) Q Q( hLet x = Male, y = Female, z = Child
- c G8 u" i& n, E) k4 n# ^公仔箱論壇6x + 3y + z/2 = 100 Formula 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) Q5 ?) p5 X) v1 d4 y
x + y + z = 100 Formula 2
6 a$ ^6 W" K" D; V% z" h& o Btvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
/ z$ Q8 t4 |+ `Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
8 |2 D. T ~: j6 ?* i* D' L公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5
, h$ m5 ?) {9 D# btvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
+ b& Q0 u$ Q6 R8 ^# PAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
6 d4 G3 z) Q- G8 V6 A9 y. i* K公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |