That is a very simple mathematics question.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" L5 j/ p2 N9 @0 w: S+ i
Let x = Male, y = Female, z = Child: h. X$ S6 p% X+ z
6x + 3y + z/2 = 100 Formula 1
' U* T$ x+ K6 R* p. A3 r) p0 k) `www3.tvboxnow.comx + y + z = 100 Formula 2
& F" m" }" q0 g* z$ y" g" S4 U公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3% n) e( \; l$ X8 M; \
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
# J- ?3 G; e8 E, L6 ]' O3 zFormula 4 can change into 11x + 5y = 100 Formula 55 s( [5 g2 P1 J5 f, c
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
" v" p% X1 b; a$ X$ T" [And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80./ l7 l4 P8 A7 }
Eventually, the answer is 20 female and 80 children and no male. |