That is a very simple mathematics question.
: T8 S9 e" q# K3 b4 N& h& e Z% xLet x = Male, y = Female, z = Child
$ \7 M+ _$ E, Y' z% ]6x + 3y + z/2 = 100 Formula 1
& I* T" g: a" f+ |+ s- C/ Ktvb now,tvbnow,bttvbx + y + z = 100 Formula 2
; ?' P6 ^/ O: G+ Q7 A5 swww3.tvboxnow.comSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
- _) u+ c4 C/ w' jSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb8 _9 T' }- M7 v8 B# v: |
Formula 4 can change into 11x + 5y = 100 Formula 5TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。4 m* w' s7 h0 O/ x. F, Z: n) [
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6 G! t5 p0 z9 M! g" Y
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb1 Z0 x* Z# T' J8 u* t( {
Eventually, the answer is 20 female and 80 children and no male. |