返回列表 回復 發帖

回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^公仔箱論壇9 Q0 v/ z6 m: M$ M
1st u divide the ball into two group (i group 6 ball)www3.tvboxnow.com; |  ]3 ~; n1 K% [
then 称 them c which side is the heavy & B- p% d- m% `8 l. i5 l) m
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb$ D7 Z" C# s) }3 B% }$ [
if not balance take the heavy and then
5 |4 T  o8 y7 m" t* mtvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it
1 t; P' k$ `/ X1 d, H* r公仔箱論壇than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: ( V2 W+ x, ]7 W/ R2 j
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
9 t) S# G4 n+ {# B, I" C6 Hwww3.tvboxnow.com然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
返回列表