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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
5 o  Q8 e; k$ R4 O% a! wwww3.tvboxnow.com将比较重的那份再平均分成两份成一次
& h6 M  U) }5 j# owww3.tvboxnow.com剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4www3.tvboxnow.com& u: k* {' t& J4 {
if  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇) D1 a3 {* R7 }  ^+ y$ w$ e' T
    then goto 2 - compare rest of(4)  - 2 with 2
6 x& z1 Z- e8 U9 }  C9 {tvb now,tvbnow,bttvb           if (left side is more weight)
1 f/ }, _: }1 x              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer公仔箱論壇. ], a: e  j+ o3 h2 B+ A( {0 I8 M# h
          else ( right side is more weight)www3.tvboxnow.com& T$ a  Y! X% T/ W9 W5 u
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
. c' U& w0 S1 K' [公仔箱論壇else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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