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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次tvb now,tvbnow,bttvb3 Q) p3 a1 W. u7 ?# a. M
将比较重的那份再平均分成两份成一次- m7 e0 v! B& {* ~5 y
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
- |2 g4 r& v/ y+ UTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if  (4v4)= same that means the rest of 4 is got more weight
+ X, k/ S' g3 ^, S% W( J6 y: [+ @    then goto 2 - compare rest of(4)  - 2 with 2
0 d. `5 S, D7 E! R8 Utvb now,tvbnow,bttvb           if (left side is more weight)
( A6 [, I4 i3 b+ g2 X8 n' ^# v+ c; q              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer  ^. g4 Q. I8 s0 B- T, Q$ m
          else ( right side is more weight)
) O/ |7 c) Z) [, W1 P              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
' T0 Y# E2 d0 [0 T' f3 p& Q/ A  x* Q2 Mwww3.tvboxnow.comelse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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