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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
# e4 ^( [; s% ?2 ]- R( Y. v将比较重的那份再平均分成两份成一次
- P, u$ m6 Q0 |. ~, F8 }剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
' w) Q9 v5 W5 I5 r$ G. Y) j5 ^% nif  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇/ s2 F, w  V7 U  q: p
    then goto 2 - compare rest of(4)  - 2 with 2 ' m0 P6 J5 l. w
           if (left side is more weight)
. O  e9 A; P) [# Y# X; ?& ~6 j& m              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
; u& \$ G) X& ?+ x, ztvb now,tvbnow,bttvb          else ( right side is more weight)
4 P* b; u! q, T; C5 K6 m3 otvb now,tvbnow,bttvb              then goto 3 - compare last (right side of (2) - 1 with 1 => get answerwww3.tvboxnow.com/ J; X6 m0 }; f5 D' T' c
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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