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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆公仔箱論壇3 s* D! V6 x- n2 F) L
共四堆www3.tvboxnow.com1 Z0 |- X- ?/ _: ?
称两次得出异常的在那一堆,其轻重
) m; K3 A1 y+ C在异常的那一堆中在称一次, F# u* c( P5 E9 V/ S  P. ^; y/ x
就可以找到了
divde the 12 balls into 3 sets of 4.
2 b0 ?. Y8 a1 A  [  h0 Kwww3.tvboxnow.comweight any 2 sets.
) m! g- @) d: q1 C& {$ }tvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third1 u! \. {5 {) W* ]& N
if one of the 2 is heavier, then the heavy one is in that setwww3.tvboxnow.com/ ?% G0 P8 j+ y: ?, k) ~& v& \! {
then divide the 4 balls into 2.www3.tvboxnow.com2 K, P  X0 G$ ]" U* B- C
weigh them
7 K% l# Y0 f+ _6 N5 wand divide the heavier into 1. g$ f' u+ Q4 ?7 X7 F% |" @" e) z) L
and weight them.1 h: y6 M( z* a% f7 x: U- U$ m& V
3 x weighing and get the ans.  tvb now,tvbnow,bttvb- H$ d7 O- G6 p* R# ?5 ]5 o: k+ k3 w
in less than 15 secs.
1. 6 aside and weight.
( ?0 R. a0 S. ]2. heavier side from (1), 3 aside weight again.www3.tvboxnow.com" u8 s1 R  I5 }. |0 E
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
) \6 w. N+ k" m$ w! a2 }# ^TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。tvb now,tvbnow,bttvb* K# t) N$ N! t& j# j# [. z
but i have a question. 重量異常 can be heavier or lighter.... so......
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