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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
- u3 [$ [5 J$ v4 o5 a9 V; J9 d公仔箱論壇共四堆$ e' s* J, ?! C4 M, g: j1 `9 v
称两次得出异常的在那一堆,其轻重tvb now,tvbnow,bttvb3 S# e. @8 y, G
在异常的那一堆中在称一次5 z" a8 w$ F# `8 {$ I
就可以找到了
divde the 12 balls into 3 sets of 4. tvb now,tvbnow,bttvb: F7 f/ d1 h/ n* |/ K9 _9 U
weight any 2 sets.
) R. `5 a3 q1 v  u4 awww3.tvboxnow.comif the 2 sets are equal, then you know the heavy one is in the thirdTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。9 A: S7 y7 B) d# C$ Y
if one of the 2 is heavier, then the heavy one is in that set
6 g8 G& `5 X; R9 K8 x4 ~then divide the 4 balls into 2.tvb now,tvbnow,bttvb  t# b* ]6 V3 ?* S2 G7 a  H
weigh them
* p! a# z! K! w6 W* G/ d公仔箱論壇and divide the heavier into 1tvb now,tvbnow,bttvb5 b9 L* k0 q+ F5 H. l- j
and weight them., S7 K9 z  I) u# N" s
3 x weighing and get the ans.  公仔箱論壇$ H5 R* |+ W1 \6 c# ~9 |
in less than 15 secs.
1. 6 aside and weight.
4 v# _% P3 {: o, g2. heavier side from (1), 3 aside weight again.
5 A* ~+ ]  ?" Fwww3.tvboxnow.com3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. www3.tvboxnow.com* n  o- H9 t6 {0 U
TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" \& t3 R/ p" V5 c
but i have a question. 重量異常 can be heavier or lighter.... so......
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