put six on each side first
- }" b4 x5 S: vtvb now,tvbnow,bttvb( [* H( t5 K& M3 F
from the heavier six, split it to three on each sidetvb now,tvbnow,bttvb+ p) c7 o, r( k& j: J
; j" J( K) b$ w公仔箱論壇then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |