hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^3 i, i9 X6 q2 S/ Q9 K0 y
1st u divide the ball into two group (i group 6 ball)
! K7 P: [* L0 Y: t公仔箱論壇then 称 them c which side is the heavy
1 q  J# f/ C7 |8 e% S  zthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group . q0 H4 Z& p1 k) _" [4 |
if not balance take the heavy and then
( j% _: N! k. e/ F- Uwww3.tvboxnow.comtake the heavy group divided into 2 group i group contain 1 ball than 称 it 公仔箱論壇* n  X9 ]: P1 J! f: E2 H0 R7 L. H
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: , |7 _; l$ v9 I# ~# ]' P6 O
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边/ u  E( J- R9 v6 e, J  I" v- n* K6 E
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me