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i find one solution that is similar2 H$ M+ h; y, g: m+ S6 E9 k
but i can't specify the heavier one is abnormal or the lighter one is abnormal when the case that has only two balls left....
9 K1 \' F3 p/ x; o+ b7 _6 v5 CTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。maybe there is a better one, let me see sin
it is already good IQ if you can understand the answer......
pretty difficult... needa see answer
!!!!!!!!!!!!!!!!!!!!!!!!!

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3 e4 {" E% D1 |5 N( T公仔箱論壇22TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。4 j7 P3 t  @9 v' g2 w
11
thanks for share:onion14:

wow

is that really possible, i want to know
interesting ...
.... thx for sharing !
ddddd
actually this question always have someone asked, the calculation is very complicated, should give a no. of each ball, and first weight it in 6-6, and .... forgot...
how oh???
Let me see the answer
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