That is a very simple mathematics question.tvb now,tvbnow,bttvb' P6 ?- B9 K) [- g7 H8 Q3 z% R
Let x = Male, y = Female, z = Child( U' I. c f2 k3 {
6x + 3y + z/2 = 100 Formula 1
& }0 Y$ M6 G/ |8 \" ]2 i/ l' zx + y + z = 100 Formula 2
' S% v) G) @/ h1 ^tvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
) G8 b0 [+ m4 ?7 d0 u- |公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
* E' q5 Q0 l3 Q; X公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5
# W# b3 r- G: p: n7 w4 n H公仔箱論壇In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
, X% ]* ~! Y+ m- r; A UTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
4 q# p& [0 x7 f. z公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |