That is a very simple mathematics question.
x$ L) y3 q: H( [9 d9 i, J( Uwww3.tvboxnow.comLet x = Male, y = Female, z = Child( R. Y7 \2 q# E
6x + 3y + z/2 = 100 Formula 1( O! y7 z U/ x3 d
x + y + z = 100 Formula 2
K3 d) Z& }9 Q/ nSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
: j& L; I; B+ R8 m0 i8 t. aTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇7 n9 }! H5 ^$ G: p7 T- p v! ~
Formula 4 can change into 11x + 5y = 100 Formula 5- {$ ^$ X+ b1 C. x: w9 ~! |
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇7 U* F8 J0 J& Q+ c
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.www3.tvboxnow.com/ }/ O: h& @; i$ p6 ]
Eventually, the answer is 20 female and 80 children and no male. |