The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。, J' b3 c ~. x& U/ w5 f! q7 a' J
www3.tvboxnow.com4 Y/ x3 W$ E% c/ x! q
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. " v. m7 h ?# Z5 U% N! |$ i
1 N$ I8 s0 }1 Ctvb now,tvbnow,bttvbNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.9 K4 `9 p. K' n$ |. ~! Q
www3.tvboxnow.com& m. ~& i1 S* L; q& @; b `7 [! D
#3 did the obvious choice 40 divided by 2 =20, so he picked 20公仔箱論壇; A* Y: i* F6 i( H
' J$ l- _4 T- C+ I# p- x#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.www3.tvboxnow.com) S* j/ L* ^7 q) O/ f/ y
0 C8 M& M+ J. e公仔箱論壇#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.公仔箱論壇$ s& C4 n6 w) r7 r
TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。* `; Z1 S h. _- e1 n$ A
Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
公仔箱論壇" Y% {5 y9 z7 D! E; H1 C0 i
