1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 " i3 ]+ I# s- W0 `公仔箱論壇For 111 would be 1x1+1=2 that is 2 times of 3rd 1 1 O9 D* C. Y& uFor 123 M1 A# |1 w. K3 |- s$ L5 e# ]1x2+1=3 that is 1 time of 3 5 h' g0 E1 V& r1 }# J& H公仔箱論壇1x3+1=4 that is 2 times of 2 6 c1 N2 {2 b8 E3 Utvb now,tvbnow,bttvb2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
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