this is too easy!!
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1. put 6 at each side.. take the one side which is heavierwww3.tvboxnow.com- H. q1 {% Q7 y: p$ H3 Q" m
2. put 3 at each side.. also take the heavier side
+ W1 O( \) ?& j) X5 D3. put 1 at each side.. if the weight balance then the one not put inside is the heavy ball.. else the side which is heavier is the heavier ball.. |
發表於 2009-1-7 05:31 AM
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