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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次公仔箱論壇/ c4 Y/ t0 c5 I5 X7 Q6 X2 L+ Z
将比较重的那份再平均分成两份成一次
0 g7 `# s3 O# L公仔箱論壇剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
( G: P  @% O$ B. f5 J5 r1 ^( k* Cif  (4v4)= same that means the rest of 4 is got more weightwww3.tvboxnow.com9 F- ?( f3 F) W( K6 w) U
    then goto 2 - compare rest of(4)  - 2 with 2
- H4 b7 U. i  T# Jwww3.tvboxnow.com           if (left side is more weight)$ d$ k4 ]; b( ?" }  i5 X4 n2 _! M2 W
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer公仔箱論壇: p2 P; y- e# ^9 |  U% v9 E! o7 n
          else ( right side is more weight)tvb now,tvbnow,bttvb- ?4 S& j( F2 d" |0 P1 D2 J
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answerwww3.tvboxnow.com* H- e* v! Y* ?$ V
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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