hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
- i, `! j+ h, |1st u divide the ball into two group (i group 6 ball)公仔箱論壇4 R+ U% g9 ^6 ?4 |
then 称 them c which side is the heavy 公仔箱論壇! g1 i) Z+ f9 B# q4 M6 K3 Q; F, m
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 3 t& _: k, D9 G' J2 ^7 H: i2 {
if not balance take the heavy and then
8 E# p9 m- ~$ Z0 K& Vtvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it
& g5 C1 r' c) r' q% l, r5 l公仔箱論壇than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇4 c; H5 y) _/ _, [; O
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
/ j5 S( @+ b& M公仔箱論壇然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me