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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^www3.tvboxnow.com6 y2 X" K  D6 U
1st u divide the ball into two group (i group 6 ball)- ~  Y: `- [. C; ]) z) n
then 称 them c which side is the heavy
8 v+ M6 M8 s! d+ z0 F2 Wthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 4 ]/ m6 G3 J$ X0 s1 E
if not balance take the heavy and then   D5 P2 f, w7 [7 h
take the heavy group divided into 2 group i group contain 1 ball than 称 it + V$ L7 G6 F9 C: }+ ]
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:   |  O5 j5 Z2 T5 p5 m6 G) A
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
& h" W% l: {6 Y& o& U2 |3 i然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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