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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
; R9 ^& i7 V! L: l3 L9 H8 V& d4 }+ I将比较重的那份再平均分成两份成一次
; Y; t# C( [" k( o# vwww3.tvboxnow.com剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4www3.tvboxnow.com& m! T4 ]' }- R; Q# y: I: H
if  (4v4)= same that means the rest of 4 is got more weight. Y- G% R2 l3 P' K
    then goto 2 - compare rest of(4)  - 2 with 2 www3.tvboxnow.com; n$ \6 U: ?% q, C( F# J5 [
           if (left side is more weight)7 P3 F! j5 I( {
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
9 t- H% O/ |8 V0 [, B          else ( right side is more weight)www3.tvboxnow.com2 k! b3 j, M4 @7 a2 T) s# ^1 O8 Y
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
( z5 q% a" ]- E- ztvb now,tvbnow,bttvbelse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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