1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 5 w- V0 L) U/ c0 p: Y eFor 111 would be 1x1+1=2 that is 2 times of 3rd 1 7 P2 K# o3 t2 [" k' t# m4 C公仔箱論壇For 123 # D- P2 Z# {- t公仔箱論壇1x2+1=3 that is 1 time of 3 ! Y+ e! W1 m! z0 O) k- \1 f公仔箱論壇1x3+1=4 that is 2 times of 2) @+ D, `5 Q' u# d( G
2x3+1=7 thta is 7 times of 1