hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
! I. |1 ^) b5 S) k( Z1st u divide the ball into two group (i group 6 ball)
, A5 q6 R  ^5 I/ `9 ]0 Z. mthen 称 them c which side is the heavy
* ~$ K5 ^8 n& `* Q公仔箱論壇then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
1 k5 S/ k; \/ Z$ Iwww3.tvboxnow.comif not balance take the heavy and then
" R* R: h2 i* P5 R8 Ntvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it
* e7 _, m3 O2 L9 |7 sthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: . l4 Y- B$ H9 e. G) z; b+ E0 D* [
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
) N9 d6 D: F; }, N然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me