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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^, h6 _# ?2 p: L. v8 L) D! [
1st u divide the ball into two group (i group 6 ball)
8 {/ n& n+ J+ T. ]% u; _! Swww3.tvboxnow.comthen 称 them c which side is the heavy
. ^1 z5 B9 `: u. tthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
% G, I8 X) M' S' s9 Zif not balance take the heavy and then 公仔箱論壇. Y: B  F: Z& `; h$ L; ^9 H3 Y- }
take the heavy group divided into 2 group i group contain 1 ball than 称 it tvb now,tvbnow,bttvb9 _& c  k, K# x  o+ b. w
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
2 P9 c; \, G  S% z(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
, ^! N* \6 p6 D5 o. v; Dtvb now,tvbnow,bttvb然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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