hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
4 Z, Z4 p4 |) P  _- i2 Dwww3.tvboxnow.com1st u divide the ball into two group (i group 6 ball)www3.tvboxnow.com* V7 [: ^3 N, X6 d! W/ k5 B2 }6 B
then 称 them c which side is the heavy 2 R$ p8 q( x3 t
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group ; [9 r4 [) W0 w  G
if not balance take the heavy and then
$ g. C0 T6 H- R* I0 _" mtake the heavy group divided into 2 group i group contain 1 ball than 称 it
$ A3 c( ^( H& V9 \# `; q9 a/ Mthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
7 U8 c( I  c2 a! `0 Z: D, otvb now,tvbnow,bttvb（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边9 N! V3 P# O+ d0 T2 p
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me