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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次7 ]% C% L' k4 {
将比较重的那份再平均分成两份成一次www3.tvboxnow.com: d' Y/ w. h* G$ u6 C. ?, w) J; y
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
/ y9 S* [2 Y3 X; o) y( vif  (4v4)= same that means the rest of 4 is got more weight
5 [6 k1 l) o1 ^, f. W( W    then goto 2 - compare rest of(4)  - 2 with 2
3 J0 ~' s6 C3 j9 [# o% @. p           if (left side is more weight)
/ |7 e( Z/ s2 Q8 h" qwww3.tvboxnow.com              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer) X& k  U% Q) c. T" D
          else ( right side is more weight)
/ Z7 e3 I0 @; X. n) s+ i+ z4 e2 c6 x6 Q- T              then goto 3 - compare last (right side of (2) - 1 with 1 => get answertvb now,tvbnow,bttvb" ^; U2 i3 ^5 G8 k" G# V. g
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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