zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。6 K! F/ s! Y: j% J5 b9 H2 x
将比较重的那份再平均分成两份成一次
" k( z# S* M8 Vtvb now,tvbnow,bttvb剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4- N; w+ A$ B7 w; x; @+ R
if  (4v4)= same that means the rest of 4 is got more weight
' A5 W& H' p9 \. t: G" l  v) R5 E    then goto 2 - compare rest of(4)  - 2 with 2 公仔箱論壇  k8 C$ ~) s3 a% n; j# w
           if (left side is more weight)
) Z9 N! V9 Z$ q: V$ Mwww3.tvboxnow.com              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer: y! z+ E9 q! j. F. ~# E
          else ( right side is more weight)
6 u. B6 q& b+ y' K7 D: Rtvb now,tvbnow,bttvb              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
" A, ]2 f  z1 \3 h2 e6 l+ Q# Melse ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。